Current Carrying Loop as a Magnetic Dipole

A nonconducting disc of radius $R$ is rotating about an axis, passing through its centre and perpendicular to its plane, with an angular velocity $\omega$. Charge $q$ is distributed uniformly over its surface. The magnetic moment of the disc is

$Q$ charge is uniformly distributed over the curve surface of a right circular cone of semi-vertical angle $\theta$ and height $h$. The cone is uniformly rotated about its axis at angular velocity $\omega$. Calculate associated magnetic dipole moment. $(h>R)$

A square current carrying loop made of thin wire and having a mass m = 10g can rotate without friction with respect to the vertical axis $\mathrm{{\rm O}}{\mathrm{{\rm O}}}_1\text{,}$passing through the centre of the loop at right angles to two opposite sides of the loop. The loop is placed in a homogeneous magnetic field with an induction $\text{B}={\text{10}}^{-1}\text{T}$directed at right angles to the plane of the drawing. A current I = 2A is flowing in the loop. Find the period of small oscillations that the loop performs about its position of stable equilibrium.

   

Circular loop having radius $r$, carrying current $I$, produces magnetic field at the centre loop is $B$. What will be the magnetic dipole moment of this loop?

What is value of bohr magneton?

In Bohr's hydrogen like atom magnetic dipole moment in ${\mathrm{n}}^{\mathrm{th}}$ orbit is expressed as.

When charged particle moves in circle then vectorial representation of magnetic dipole moment is ( if $\overrightarrow{\mathrm{L}}$ is angular momentum)

An electron revolves around the nucleus of hydrogen like atom then magnetic moment of electron is

A nonconducting disc of radius $R$ is rotating about an axis, passing through its centre and perpendicular to its plane, with an angular velocity $\omega$. Charge $q$ is distributed uniformly over its surface. The magnetic moment of the disc is

A charge $q$ is spread uniformly over an insulated loop of radius $r$. If it is rotated with an angular velocity $\omega$ with respect to the normal axis then a magnetic moment of the loop is:

A non-conducting rod of length $L$ with linear charge density $\lambda ={\lambda }_{0}x$ where $x$ is the distance from end $A$ is rotating with constant angular speed $\omega$ about the same end. If the angular velocity of the rod $\left(\omega \right)$ is large, then the magnetic dipole moment of the system is $\frac{\omega {\lambda }_0{L}^4}{n}$. What is the value of $n$?

A magnetic wire of dipole moment $4\mathrm{\pi } \mathrm{A} {\mathrm{m}}^2$ is bent in the form of semicircle. The new magnetic moment is

The magnetic dipole moment of current loop is independent of

A circular loop and a square loop are formed from two wires of same length and cross-section. Same current is passed through them. Then the ratio of their dipole moments is

A square loop is carrying a steady current $\mathrm{I}\mathrm{ }$ and the magnitude of its magnetic dipole moment is $\mathrm{m}$ . If this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be:

Following figures show the arrangement of bar magnets in different configurations. Each magnet has magnetic dipole $\overrightarrow{m}.$ Which configuration has highest net magnetic dipole moment?

A wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of a circle. Its magnitude of the magnetic moment will be:

A circular coil of $300$ turns and diameter $14 \mathrm{cm}$ carries a current of $15 \mathrm{A}$. Magnitude of the magnetic dipole moment associated with the coil is 

A negatively charged particle is revolving in a circle of radius $r$ out of the following which one figure represents the correct direction of $\overrightarrow{\mathit{L}}$ and $\overrightarrow{M}$ ($L$ is the angular momentum of the particle and $\overrightarrow{M}$ is the magnetic moment of the particle):

The magnetic dipole moment of a current loop is independent of